3.1.13 \(\int x^5 (a+b \text {ArcTan}(c x))^2 \, dx\) [13]

Optimal. Leaf size=144 \[ -\frac {a b x}{3 c^5}-\frac {4 b^2 x^2}{45 c^4}+\frac {b^2 x^4}{60 c^2}-\frac {b^2 x \text {ArcTan}(c x)}{3 c^5}+\frac {b x^3 (a+b \text {ArcTan}(c x))}{9 c^3}-\frac {b x^5 (a+b \text {ArcTan}(c x))}{15 c}+\frac {(a+b \text {ArcTan}(c x))^2}{6 c^6}+\frac {1}{6} x^6 (a+b \text {ArcTan}(c x))^2+\frac {23 b^2 \log \left (1+c^2 x^2\right )}{90 c^6} \]

[Out]

-1/3*a*b*x/c^5-4/45*b^2*x^2/c^4+1/60*b^2*x^4/c^2-1/3*b^2*x*arctan(c*x)/c^5+1/9*b*x^3*(a+b*arctan(c*x))/c^3-1/1
5*b*x^5*(a+b*arctan(c*x))/c+1/6*(a+b*arctan(c*x))^2/c^6+1/6*x^6*(a+b*arctan(c*x))^2+23/90*b^2*ln(c^2*x^2+1)/c^
6

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Rubi [A]
time = 0.22, antiderivative size = 144, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 7, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {4946, 5036, 272, 45, 4930, 266, 5004} \begin {gather*} \frac {(a+b \text {ArcTan}(c x))^2}{6 c^6}+\frac {b x^3 (a+b \text {ArcTan}(c x))}{9 c^3}+\frac {1}{6} x^6 (a+b \text {ArcTan}(c x))^2-\frac {b x^5 (a+b \text {ArcTan}(c x))}{15 c}-\frac {a b x}{3 c^5}-\frac {b^2 x \text {ArcTan}(c x)}{3 c^5}-\frac {4 b^2 x^2}{45 c^4}+\frac {b^2 x^4}{60 c^2}+\frac {23 b^2 \log \left (c^2 x^2+1\right )}{90 c^6} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^5*(a + b*ArcTan[c*x])^2,x]

[Out]

-1/3*(a*b*x)/c^5 - (4*b^2*x^2)/(45*c^4) + (b^2*x^4)/(60*c^2) - (b^2*x*ArcTan[c*x])/(3*c^5) + (b*x^3*(a + b*Arc
Tan[c*x]))/(9*c^3) - (b*x^5*(a + b*ArcTan[c*x]))/(15*c) + (a + b*ArcTan[c*x])^2/(6*c^6) + (x^6*(a + b*ArcTan[c
*x])^2)/6 + (23*b^2*Log[1 + c^2*x^2])/(90*c^6)

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 266

Int[(x_)^(m_.)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> Simp[Log[RemoveContent[a + b*x^n, x]]/(b*n), x] /; FreeQ
[{a, b, m, n}, x] && EqQ[m, n - 1]

Rule 272

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 4930

Int[((a_.) + ArcTan[(c_.)*(x_)^(n_.)]*(b_.))^(p_.), x_Symbol] :> Simp[x*(a + b*ArcTan[c*x^n])^p, x] - Dist[b*c
*n*p, Int[x^n*((a + b*ArcTan[c*x^n])^(p - 1)/(1 + c^2*x^(2*n))), x], x] /; FreeQ[{a, b, c, n}, x] && IGtQ[p, 0
] && (EqQ[n, 1] || EqQ[p, 1])

Rule 4946

Int[((a_.) + ArcTan[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)*((a + b*ArcTan[c*x^
n])^p/(m + 1)), x] - Dist[b*c*n*(p/(m + 1)), Int[x^(m + n)*((a + b*ArcTan[c*x^n])^(p - 1)/(1 + c^2*x^(2*n))),
x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0] && (EqQ[p, 1] || (EqQ[n, 1] && IntegerQ[m])) && NeQ[m, -1]

Rule 5004

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)/((d_) + (e_.)*(x_)^2), x_Symbol] :> Simp[(a + b*ArcTan[c*x])^(p +
1)/(b*c*d*(p + 1)), x] /; FreeQ[{a, b, c, d, e, p}, x] && EqQ[e, c^2*d] && NeQ[p, -1]

Rule 5036

Int[(((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*((f_.)*(x_))^(m_))/((d_) + (e_.)*(x_)^2), x_Symbol] :> Dist[f^2/
e, Int[(f*x)^(m - 2)*(a + b*ArcTan[c*x])^p, x], x] - Dist[d*(f^2/e), Int[(f*x)^(m - 2)*((a + b*ArcTan[c*x])^p/
(d + e*x^2)), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[p, 0] && GtQ[m, 1]

Rubi steps

\begin {align*} \int x^5 \left (a+b \tan ^{-1}(c x)\right )^2 \, dx &=\frac {1}{6} x^6 \left (a+b \tan ^{-1}(c x)\right )^2-\frac {1}{3} (b c) \int \frac {x^6 \left (a+b \tan ^{-1}(c x)\right )}{1+c^2 x^2} \, dx\\ &=\frac {1}{6} x^6 \left (a+b \tan ^{-1}(c x)\right )^2-\frac {b \int x^4 \left (a+b \tan ^{-1}(c x)\right ) \, dx}{3 c}+\frac {b \int \frac {x^4 \left (a+b \tan ^{-1}(c x)\right )}{1+c^2 x^2} \, dx}{3 c}\\ &=-\frac {b x^5 \left (a+b \tan ^{-1}(c x)\right )}{15 c}+\frac {1}{6} x^6 \left (a+b \tan ^{-1}(c x)\right )^2+\frac {1}{15} b^2 \int \frac {x^5}{1+c^2 x^2} \, dx+\frac {b \int x^2 \left (a+b \tan ^{-1}(c x)\right ) \, dx}{3 c^3}-\frac {b \int \frac {x^2 \left (a+b \tan ^{-1}(c x)\right )}{1+c^2 x^2} \, dx}{3 c^3}\\ &=\frac {b x^3 \left (a+b \tan ^{-1}(c x)\right )}{9 c^3}-\frac {b x^5 \left (a+b \tan ^{-1}(c x)\right )}{15 c}+\frac {1}{6} x^6 \left (a+b \tan ^{-1}(c x)\right )^2+\frac {1}{30} b^2 \text {Subst}\left (\int \frac {x^2}{1+c^2 x} \, dx,x,x^2\right )-\frac {b \int \left (a+b \tan ^{-1}(c x)\right ) \, dx}{3 c^5}+\frac {b \int \frac {a+b \tan ^{-1}(c x)}{1+c^2 x^2} \, dx}{3 c^5}-\frac {b^2 \int \frac {x^3}{1+c^2 x^2} \, dx}{9 c^2}\\ &=-\frac {a b x}{3 c^5}+\frac {b x^3 \left (a+b \tan ^{-1}(c x)\right )}{9 c^3}-\frac {b x^5 \left (a+b \tan ^{-1}(c x)\right )}{15 c}+\frac {\left (a+b \tan ^{-1}(c x)\right )^2}{6 c^6}+\frac {1}{6} x^6 \left (a+b \tan ^{-1}(c x)\right )^2+\frac {1}{30} b^2 \text {Subst}\left (\int \left (-\frac {1}{c^4}+\frac {x}{c^2}+\frac {1}{c^4 \left (1+c^2 x\right )}\right ) \, dx,x,x^2\right )-\frac {b^2 \int \tan ^{-1}(c x) \, dx}{3 c^5}-\frac {b^2 \text {Subst}\left (\int \frac {x}{1+c^2 x} \, dx,x,x^2\right )}{18 c^2}\\ &=-\frac {a b x}{3 c^5}-\frac {b^2 x^2}{30 c^4}+\frac {b^2 x^4}{60 c^2}-\frac {b^2 x \tan ^{-1}(c x)}{3 c^5}+\frac {b x^3 \left (a+b \tan ^{-1}(c x)\right )}{9 c^3}-\frac {b x^5 \left (a+b \tan ^{-1}(c x)\right )}{15 c}+\frac {\left (a+b \tan ^{-1}(c x)\right )^2}{6 c^6}+\frac {1}{6} x^6 \left (a+b \tan ^{-1}(c x)\right )^2+\frac {b^2 \log \left (1+c^2 x^2\right )}{30 c^6}+\frac {b^2 \int \frac {x}{1+c^2 x^2} \, dx}{3 c^4}-\frac {b^2 \text {Subst}\left (\int \left (\frac {1}{c^2}-\frac {1}{c^2 \left (1+c^2 x\right )}\right ) \, dx,x,x^2\right )}{18 c^2}\\ &=-\frac {a b x}{3 c^5}-\frac {4 b^2 x^2}{45 c^4}+\frac {b^2 x^4}{60 c^2}-\frac {b^2 x \tan ^{-1}(c x)}{3 c^5}+\frac {b x^3 \left (a+b \tan ^{-1}(c x)\right )}{9 c^3}-\frac {b x^5 \left (a+b \tan ^{-1}(c x)\right )}{15 c}+\frac {\left (a+b \tan ^{-1}(c x)\right )^2}{6 c^6}+\frac {1}{6} x^6 \left (a+b \tan ^{-1}(c x)\right )^2+\frac {23 b^2 \log \left (1+c^2 x^2\right )}{90 c^6}\\ \end {align*}

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Mathematica [A]
time = 0.09, size = 138, normalized size = 0.96 \begin {gather*} \frac {c x \left (30 a^2 c^5 x^5+b^2 c x \left (-16+3 c^2 x^2\right )-4 a b \left (15-5 c^2 x^2+3 c^4 x^4\right )\right )+4 b \left (b c x \left (-15+5 c^2 x^2-3 c^4 x^4\right )+15 a \left (1+c^6 x^6\right )\right ) \text {ArcTan}(c x)+30 b^2 \left (1+c^6 x^6\right ) \text {ArcTan}(c x)^2+46 b^2 \log \left (1+c^2 x^2\right )}{180 c^6} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^5*(a + b*ArcTan[c*x])^2,x]

[Out]

(c*x*(30*a^2*c^5*x^5 + b^2*c*x*(-16 + 3*c^2*x^2) - 4*a*b*(15 - 5*c^2*x^2 + 3*c^4*x^4)) + 4*b*(b*c*x*(-15 + 5*c
^2*x^2 - 3*c^4*x^4) + 15*a*(1 + c^6*x^6))*ArcTan[c*x] + 30*b^2*(1 + c^6*x^6)*ArcTan[c*x]^2 + 46*b^2*Log[1 + c^
2*x^2])/(180*c^6)

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Maple [A]
time = 0.33, size = 171, normalized size = 1.19

method	result	size
derivativedivides	\(\frac {\frac {c^{6} x^{6} a^{2}}{6}+\frac {b^{2} c^{6} x^{6} \arctan \left (c x \right )^{2}}{6}-\frac {b^{2} \arctan \left (c x \right ) c^{5} x^{5}}{15}+\frac {b^{2} \arctan \left (c x \right ) c^{3} x^{3}}{9}-\frac {b^{2} \arctan \left (c x \right ) c x}{3}+\frac {b^{2} \arctan \left (c x \right )^{2}}{6}+\frac {b^{2} c^{4} x^{4}}{60}-\frac {4 b^{2} c^{2} x^{2}}{45}+\frac {23 b^{2} \ln \left (c^{2} x^{2}+1\right )}{90}+\frac {a b \,c^{6} x^{6} \arctan \left (c x \right )}{3}-\frac {c^{5} x^{5} a b}{15}+\frac {a b \,c^{3} x^{3}}{9}-\frac {a b c x}{3}+\frac {a b \arctan \left (c x \right )}{3}}{c^{6}}\)	\(171\)
default	\(\frac {\frac {c^{6} x^{6} a^{2}}{6}+\frac {b^{2} c^{6} x^{6} \arctan \left (c x \right )^{2}}{6}-\frac {b^{2} \arctan \left (c x \right ) c^{5} x^{5}}{15}+\frac {b^{2} \arctan \left (c x \right ) c^{3} x^{3}}{9}-\frac {b^{2} \arctan \left (c x \right ) c x}{3}+\frac {b^{2} \arctan \left (c x \right )^{2}}{6}+\frac {b^{2} c^{4} x^{4}}{60}-\frac {4 b^{2} c^{2} x^{2}}{45}+\frac {23 b^{2} \ln \left (c^{2} x^{2}+1\right )}{90}+\frac {a b \,c^{6} x^{6} \arctan \left (c x \right )}{3}-\frac {c^{5} x^{5} a b}{15}+\frac {a b \,c^{3} x^{3}}{9}-\frac {a b c x}{3}+\frac {a b \arctan \left (c x \right )}{3}}{c^{6}}\)	\(171\)
risch	\(-\frac {b^{2} \left (c^{6} x^{6}+1\right ) \ln \left (i c x +1\right )^{2}}{24 c^{6}}-\frac {i b \left (30 c^{6} x^{6} a +15 i b \,c^{6} x^{6} \ln \left (-i c x +1\right )-6 b \,c^{5} x^{5}+10 b \,c^{3} x^{3}-30 x b c +15 i b \ln \left (-i c x +1\right )\right ) \ln \left (i c x +1\right )}{180 c^{6}}-\frac {b^{2} x^{6} \ln \left (-i c x +1\right )^{2}}{24}-\frac {i b^{2} x \ln \left (-i c x +1\right )}{6 c^{5}}+\frac {i b^{2} x^{3} \ln \left (-i c x +1\right )}{18 c^{3}}+\frac {a^{2} x^{6}}{6}-\frac {x^{5} a b}{15 c}-\frac {i b^{2} x^{5} \ln \left (-i c x +1\right )}{30 c}+\frac {b^{2} x^{4}}{60 c^{2}}+\frac {a b \,x^{3}}{9 c^{3}}+\frac {i a b \,x^{6} \ln \left (-i c x +1\right )}{6}-\frac {4 b^{2} x^{2}}{45 c^{4}}-\frac {b^{2} \ln \left (-i c x +1\right )^{2}}{24 c^{6}}-\frac {a b x}{3 c^{5}}+\frac {a b \arctan \left (c x \right )}{3 c^{6}}+\frac {23 b^{2} \ln \left (c^{2} x^{2}+1\right )}{90 c^{6}}\)	\(304\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5*(a+b*arctan(c*x))^2,x,method=_RETURNVERBOSE)

[Out]

1/c^6*(1/6*c^6*x^6*a^2+1/6*b^2*c^6*x^6*arctan(c*x)^2-1/15*b^2*arctan(c*x)*c^5*x^5+1/9*b^2*arctan(c*x)*c^3*x^3-
1/3*b^2*arctan(c*x)*c*x+1/6*b^2*arctan(c*x)^2+1/60*b^2*c^4*x^4-4/45*b^2*c^2*x^2+23/90*b^2*ln(c^2*x^2+1)+1/3*a*
b*c^6*x^6*arctan(c*x)-1/15*c^5*x^5*a*b+1/9*a*b*c^3*x^3-1/3*a*b*c*x+1/3*a*b*arctan(c*x))

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Maxima [A]
time = 0.48, size = 163, normalized size = 1.13 \begin {gather*} \frac {1}{6} \, b^{2} x^{6} \arctan \left (c x\right )^{2} + \frac {1}{6} \, a^{2} x^{6} + \frac {1}{45} \, {\left (15 \, x^{6} \arctan \left (c x\right ) - c {\left (\frac {3 \, c^{4} x^{5} - 5 \, c^{2} x^{3} + 15 \, x}{c^{6}} - \frac {15 \, \arctan \left (c x\right )}{c^{7}}\right )}\right )} a b - \frac {1}{180} \, {\left (4 \, c {\left (\frac {3 \, c^{4} x^{5} - 5 \, c^{2} x^{3} + 15 \, x}{c^{6}} - \frac {15 \, \arctan \left (c x\right )}{c^{7}}\right )} \arctan \left (c x\right ) - \frac {3 \, c^{4} x^{4} - 16 \, c^{2} x^{2} - 30 \, \arctan \left (c x\right )^{2} + 46 \, \log \left (c^{2} x^{2} + 1\right )}{c^{6}}\right )} b^{2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5*(a+b*arctan(c*x))^2,x, algorithm="maxima")

[Out]

1/6*b^2*x^6*arctan(c*x)^2 + 1/6*a^2*x^6 + 1/45*(15*x^6*arctan(c*x) - c*((3*c^4*x^5 - 5*c^2*x^3 + 15*x)/c^6 - 1
5*arctan(c*x)/c^7))*a*b - 1/180*(4*c*((3*c^4*x^5 - 5*c^2*x^3 + 15*x)/c^6 - 15*arctan(c*x)/c^7)*arctan(c*x) - (
3*c^4*x^4 - 16*c^2*x^2 - 30*arctan(c*x)^2 + 46*log(c^2*x^2 + 1))/c^6)*b^2

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Fricas [A]
time = 0.83, size = 152, normalized size = 1.06 \begin {gather*} \frac {30 \, a^{2} c^{6} x^{6} - 12 \, a b c^{5} x^{5} + 3 \, b^{2} c^{4} x^{4} + 20 \, a b c^{3} x^{3} - 16 \, b^{2} c^{2} x^{2} - 60 \, a b c x + 30 \, {\left (b^{2} c^{6} x^{6} + b^{2}\right )} \arctan \left (c x\right )^{2} + 46 \, b^{2} \log \left (c^{2} x^{2} + 1\right ) + 4 \, {\left (15 \, a b c^{6} x^{6} - 3 \, b^{2} c^{5} x^{5} + 5 \, b^{2} c^{3} x^{3} - 15 \, b^{2} c x + 15 \, a b\right )} \arctan \left (c x\right )}{180 \, c^{6}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5*(a+b*arctan(c*x))^2,x, algorithm="fricas")

[Out]

1/180*(30*a^2*c^6*x^6 - 12*a*b*c^5*x^5 + 3*b^2*c^4*x^4 + 20*a*b*c^3*x^3 - 16*b^2*c^2*x^2 - 60*a*b*c*x + 30*(b^
2*c^6*x^6 + b^2)*arctan(c*x)^2 + 46*b^2*log(c^2*x^2 + 1) + 4*(15*a*b*c^6*x^6 - 3*b^2*c^5*x^5 + 5*b^2*c^3*x^3 -
15*b^2*c*x + 15*a*b)*arctan(c*x))/c^6

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Sympy [A]
time = 0.46, size = 199, normalized size = 1.38 \begin {gather*} \begin {cases} \frac {a^{2} x^{6}}{6} + \frac {a b x^{6} \operatorname {atan}{\left (c x \right )}}{3} - \frac {a b x^{5}}{15 c} + \frac {a b x^{3}}{9 c^{3}} - \frac {a b x}{3 c^{5}} + \frac {a b \operatorname {atan}{\left (c x \right )}}{3 c^{6}} + \frac {b^{2} x^{6} \operatorname {atan}^{2}{\left (c x \right )}}{6} - \frac {b^{2} x^{5} \operatorname {atan}{\left (c x \right )}}{15 c} + \frac {b^{2} x^{4}}{60 c^{2}} + \frac {b^{2} x^{3} \operatorname {atan}{\left (c x \right )}}{9 c^{3}} - \frac {4 b^{2} x^{2}}{45 c^{4}} - \frac {b^{2} x \operatorname {atan}{\left (c x \right )}}{3 c^{5}} + \frac {23 b^{2} \log {\left (x^{2} + \frac {1}{c^{2}} \right )}}{90 c^{6}} + \frac {b^{2} \operatorname {atan}^{2}{\left (c x \right )}}{6 c^{6}} & \text {for}\: c \neq 0 \\\frac {a^{2} x^{6}}{6} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**5*(a+b*atan(c*x))**2,x)

[Out]

Piecewise((a**2*x**6/6 + a*b*x**6*atan(c*x)/3 - a*b*x**5/(15*c) + a*b*x**3/(9*c**3) - a*b*x/(3*c**5) + a*b*ata
n(c*x)/(3*c**6) + b**2*x**6*atan(c*x)**2/6 - b**2*x**5*atan(c*x)/(15*c) + b**2*x**4/(60*c**2) + b**2*x**3*atan
(c*x)/(9*c**3) - 4*b**2*x**2/(45*c**4) - b**2*x*atan(c*x)/(3*c**5) + 23*b**2*log(x**2 + c**(-2))/(90*c**6) + b
**2*atan(c*x)**2/(6*c**6), Ne(c, 0)), (a**2*x**6/6, True))

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5*(a+b*arctan(c*x))^2,x, algorithm="giac")

[Out]

sage0*x

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Mupad [B]
time = 0.67, size = 171, normalized size = 1.19 \begin {gather*} \frac {30\,b^2\,{\mathrm {atan}\left (c\,x\right )}^2+46\,b^2\,\ln \left (c^2\,x^2+1\right )+30\,a^2\,c^6\,x^6-16\,b^2\,c^2\,x^2+3\,b^2\,c^4\,x^4+60\,a\,b\,\mathrm {atan}\left (c\,x\right )+20\,b^2\,c^3\,x^3\,\mathrm {atan}\left (c\,x\right )-12\,b^2\,c^5\,x^5\,\mathrm {atan}\left (c\,x\right )-60\,b^2\,c\,x\,\mathrm {atan}\left (c\,x\right )+30\,b^2\,c^6\,x^6\,{\mathrm {atan}\left (c\,x\right )}^2+20\,a\,b\,c^3\,x^3-12\,a\,b\,c^5\,x^5-60\,a\,b\,c\,x+60\,a\,b\,c^6\,x^6\,\mathrm {atan}\left (c\,x\right )}{180\,c^6} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5*(a + b*atan(c*x))^2,x)

[Out]

(30*b^2*atan(c*x)^2 + 46*b^2*log(c^2*x^2 + 1) + 30*a^2*c^6*x^6 - 16*b^2*c^2*x^2 + 3*b^2*c^4*x^4 + 60*a*b*atan(
c*x) + 20*b^2*c^3*x^3*atan(c*x) - 12*b^2*c^5*x^5*atan(c*x) - 60*b^2*c*x*atan(c*x) + 30*b^2*c^6*x^6*atan(c*x)^2
+ 20*a*b*c^3*x^3 - 12*a*b*c^5*x^5 - 60*a*b*c*x + 60*a*b*c^6*x^6*atan(c*x))/(180*c^6)

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